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X^2+30X+16=0
a = 1; b = 30; c = +16;
Δ = b2-4ac
Δ = 302-4·1·16
Δ = 836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{836}=\sqrt{4*209}=\sqrt{4}*\sqrt{209}=2\sqrt{209}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{209}}{2*1}=\frac{-30-2\sqrt{209}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{209}}{2*1}=\frac{-30+2\sqrt{209}}{2} $
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